Question

In a group of $26$ persons $8$ take tea but not coffee and $16$ take tea. How many of them take coffee but not tea?

Answer 1

$T=$ $\text{persons drinking tea}$

$C$ $=\text{persons drinking coffee}$

$n(T\cup C)=26$

$\text{8 take Tea but not Coffee}$ $=n(T\cap \overline{C})=8$,

$\text{people who take Tea}$ $=n\left(T\right)=16$

$\text{people take coffee but not tea}$ $=n(\overline{T}\cap C)=n(T\cup C)-n\left(T\right)=26-16=10$