In a group of $6$ boys are $4$ girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there

109

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128

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138

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209

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Solution

The correct option is C $209$
Out of $10$ children, four children are to be selected.
Total number of ways $=^{10} C_{4}$
No of ways when there would no girls $=^{4} C_{4}$
Number of ways when at least one boy would be there $210 - 1$ $= 209$

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In a group of 6 boys are 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there

The correct option is C 209Out of 10 children, four children are to be selected.Total number of ways= 10C4No of ways when there would no girls = 4C4Number of ways when at least one boy would be there 210−1=209

In a group of $6$ boys are $4$ girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there

The correct option is C $209$
Out of $10$ children, four children are to be selected.
Total number of ways $=^{10} C_{4}$
No of ways when there would no girls $=^{4} C_{4}$
Number of ways when at least one boy would be there $210 - 1$ $= 209$