In a group of 70 people, 37 like coffee, 52 like tea and each person like at least one of the two drinks. The number of persons liking both coffee and tea is:

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Solution

The correct option is C
19

$n (A \cup B)$ = $n (A) + n (B) - n (A \cap B)$

We have, 70 = 37 + 52 - $n (A \cap B)$
$n (A \cap B)$ = 19.

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In a group of 70 people, 37 like coffee, 52 like tea and each person like at least one of the two drinks. The number of persons liking both coffee and tea is:

The correct option is C 19 n(A∪B) = n(A)+n(B)−n(A∩B) We have, 70 = 37 + 52 - n(A∩B) n(A∩B) = 19.

The correct option is C
19

$n (A \cup B)$ = $n (A) + n (B) - n (A \cap B)$

We have, 70 = 37 + 52 - $n (A \cap B)$
$n (A \cap B)$ = 19.