Question

In a group of equal number of men and women,$10$% of men and $45$% of women are unemployed. The probability that a person selected at random from that group is employed is

• A. $\frac{11}{40}$
• B. $\frac{29}{40}$
• C. $\frac{18}{40}$
• D. $\frac{9}{40}$

Answer 1

Answer: (B)

$\frac{29}{40}$

Let there be $100$ men and $100$ women.
Number of employed men = $90$
Number of employed women = $55$
Hence, total number of employed people = $90+55=145$
Hence, required probability = $\frac{145}{200}=\frac{29}{40}$