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Standard XII

Chemistry

Nernst Equation

In a H2-O2 fu...

Question

In a $H_{2} - O_{2}$ fuel cell, 8.96 L of hydrogen at STP reacts in 15 minutes. The average current produced in amperes is:

8.577 a m p

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85.77 a m p

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857.7 a m p

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8577 a m p

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Solution

The correct option is B $85.77 a m p$
Applying Farady's first law:
$\frac{Q}{F} = mole \times V . f \frac{I t}{F} = mole \times V . f \frac{I t}{F} = \frac{8.96}{22.4} \times 2$

$I = \frac{8.96 \times F}{22.4 \times 15 \times 60} \times 2 = 85.77 a m p$

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In a H2−O2 fuel cell, 8.96 L of hydrogen at STP reacts in 15 minutes.​ The average current produced in amperes is:​

The correct option is B 85.77 ampApplying Farady's first law: QF=mole×V.fItF=mole×V.fItF=8.9622.4×2 I=8.96×F22.4×15×60×2=85.77 amp

In a $H_{2} - O_{2}$ fuel cell, 8.96 L of hydrogen at STP reacts in 15 minutes. The average current produced in amperes is:

The correct option is B $85.77 a m p$
Applying Farady's first law:
$\frac{Q}{F} = mole \times V . f \frac{I t}{F} = mole \times V . f \frac{I t}{F} = \frac{8.96}{22.4} \times 2$

$I = \frac{8.96 \times F}{22.4 \times 15 \times 60} \times 2 = 85.77 a m p$