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Question

In a H atom, if 'x' is the radius of the first Bohr orbit, the de Broglie wavelength of an electron in the third Bohr orbit is

A
3πx
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B
6πx
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C
9x2
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D
x22
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Solution

The correct option is B 6πx
The radius of the first Bohr orbit of the H atom is 0.529oA
Therefore, x=0.529oA
rn=0.529×n2zoA
where, n= number of orbits
So, if r1=x,then r3=32x=9x
And λ=2πrn
2π(9x)n=6πx

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