In a H-like sample, electrons make transition from 5th excited state to 2nd excited state. Then:
A
10 different spectral lines will be emitted
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B
6 different spectral lines will be emitted
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C
Number of lines belonging to Balmer series will be 4
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D
Number of lines belonging to paschen series will be 3
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Solution
The correct options are B Number of lines belonging to paschen series will be 3 C 6 different spectral lines will be emitted As we know, no. of emitted line will be (n2−n1)(n2−n1+1)2=(6−3)(6−3+1)2=6 And out of these six lines, three lines will belongs to paschen series.