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Question

In a H-like sample, electrons make transition from 5th excited state to 2nd excited state. Then:

A
10 different spectral lines will be emitted
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B
6 different spectral lines will be emitted
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C
Number of lines belonging to Balmer series will be 4
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D
Number of lines belonging to paschen series will be 3
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Solution

The correct options are
B Number of lines belonging to paschen series will be 3
C 6 different spectral lines will be emitted
As we know, no. of emitted line will be (n2n1)(n2n1+1)2=(63)(63+1)2=6
And out of these six lines, three lines will belongs to paschen series.

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