wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a H.P, tn = 1n . The Harmonic mean of first 10 terms of H.P is


A

5/11

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

2/11

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

-5/11

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

-2/11

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

2/11


Given tn = 1n

1, 12, 13,--------- forms H.P.

H.M. of n positive numbers xn, x2,----------- xn is,

H.M. = n1x1+1x2+.......+1xn

Hence, H.M. of given H.P. = 101+2+3+......+10

= 10×210×11 [∑ n = n(n+1)2 ]

= 211

Short cut:- If a1, a2,----------- an form H.P.

H.M. of all 'n' terms = 2a1ana1+an

Here a1 = 1 an = 110 hence H M = 2×1101+110 = 211


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Harmonic Progression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon