In a high spin octahedral complex- the d 7 configuration according to CFT isA- t2 g 4- e 3 gB- t2 g5- e2 gC- t2 g3- e4 gD- t2 g- e1 g

The correct option is B t^5_2g,e^2gHigh spin complex means ligand is weak, hence, Δ_0 lt; P (pairing energy) ...

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Standard XII

Chemistry

Filling Up Electrons in Field Split Orbitals

In a high spi...

Question

In a high spin octahedral complex, the $d^{7}$ configuration according to CFT is

t_{2 g}^{6}, e^{1} g

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t_{2 g}^{4}, e^{3} g

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t_{2 g}^{3}, e^{4} g

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t_{2 g}^{5}, e^{2} g

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Solution

The correct option is D $t_{2 g}^{5}, e^{2} g$
High spin complex means ligand is weak, hence, $Δ_{0}$ < P (pairing energy)

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Similar questions

Q. In a high spin octahedral complex, the

d^{7}

configuration according to CFT is

If $Δ_{\circ}$ > P (P = pairing energy; $Δ_{\circ}$ change in energy of octahedral complexes), the correct electronic configuration for $d^{4}$ system will be

According to CFT , in the octahedral complexes the d orbital splits into

Q. For which of the following

d^{n}

configuration of octahedral complex(ex), cannot exist in both high spin and low spin forms?

The octahedral complex ions

[F e C l_{6}]^{3 -}

and

[F e (C N)_{6}]^{3 -}

are both paramagnetic but the former is high spin and the latter is low spin. In the high spin complex,

[F e C l_{6}]^{3 -}

has the d-configuration as :

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In a high spin octahedral complex, the d7 configuration according to CFT is

The correct option is D t52g,e2gHigh spin complex means ligand is weak, hence, Δ0 < P (pairing energy)

In a high spin octahedral complex, the $d^{7}$ configuration according to CFT is

The correct option is D $t_{2 g}^{5}, e^{2} g$
High spin complex means ligand is weak, hence, $Δ_{0}$ < P (pairing energy)