CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

In a historical experiment to determine Planck's constant, a metal surface was irradiated with light of different wavelengths. The emitted photoelectric energies were measured by applying a stopping potential. The relevant data for the wavelength (λ) of incident light at the corresponding stopping potential (V0) are given below:

λ(μm) V0 (Volt)
0.3 2.0
0.4 1.0
0.5 0.4

Given, c=3×108 ms1 and e=1.6×1019 C, Planck's constant (in units of Js) from such an experiment is

A
6.0×1034
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6.4×1034
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6.6×1034
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6.8×1034
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 6.4×1034
Einstein's Photoelectric equation
hcλϕ=eV0
From the given data;
for first wavelenghthc0.3×106ϕ=2e .....(1)

for secound wavelenghthc0.4×106ϕ=e .....(2)
Subtracting (1) to (2), we get,
hc(10.310.4)106=e
where, c=3×108 ms1 and e=1.6×1019 C
h×(3×108)(10.310.4)106=1.6×1019
h=6.4×1034 Js

flag
Suggest Corrections
thumbs-up
2
BNAT
mid-banner-image
similar_icon
Similar questions
View More