In a hockey championship, three were $153$ matches played. Every two teams played one match with each other. The number of teams participating in the championship is:

Open in App

Solution

Let the no.of terms be 'n'
then matches Played b/w '2' terms
is $^{n} C_{2} = 153 \Rightarrow \frac{n!}{(n - 2)! 2!} = 153$
$\Rightarrow n (n - 1) = 306 \Rightarrow n = 18$

Suggest Corrections

Similar questions

Q. In a hockey championship, there were 153 matches played. Every two teams played one match with each other. The number of teams participating in the championship is

Q. In a football championship, there were played 153 matches. Every two teams played one match with each other. The number of teams, participating in the championship is ...........

Q. In football championship,

153

matches were played. Every team played one match with each other. The number of teams participating in the championship is-

Q. In a football championship, there were played 153 matches. Every team played one match with each other. The number of teams participating in the championship is

In a hockey championship, there are 136 matches played. Every team played one match with every other team. The number of teams participating in the championship is?

Join BYJU'S Learning Program

In a hockey championship, three were 153 matches played. Every two teams played one match with each other. The number of teams participating in the championship is:

Let the no.of terms be 'n' then matches Played b/w '2' termsis nC2=153⇒n!(n−2)!2!=153⇒n(n−1)=306⇒n=18

In a hockey championship, three were $153$ matches played. Every two teams played one match with each other. The number of teams participating in the championship is:

Let the no.of terms be 'n'
then matches Played b/w '2' terms
is $^{n} C_{2} = 153 \Rightarrow \frac{n!}{(n - 2)! 2!} = 153$
$\Rightarrow n (n - 1) = 306 \Rightarrow n = 18$