Question

In a homogeneous catalytic reaction, $1.0M$ of a subtract band $1.0\mu M$ of a catalyst yields $1.0mM$ of a product in $10s$. the turnover frequency $\left(TOF\right)$ of the reaction ($s^{-1}$) is:

• A. ${10}^{-2}$
• B. ${10}^2$
• C. ${10}^{-3}$
• D. ${10}^3$

Answer 1

The correct option is B ${10}^2$

No. of molecule of substrate converted into product $={10}^{-3}M$
No. of molecule of catalyst used $=1.0\mu M={10}^{-6}M$

Times taken $=10sec$

T.O.F$=\frac{No.ofmoleculeproductformedfromsubstrate}{No.ofmoleculeofcatalystused\times time}$

T.O.F$=\frac{{10}^{-3}M}{{10}^{-6}M\times 10sec}$

TOF$={10}^{2}se{c}^{-1}$

Thus turn over frequency is ${10}^{2}se{c}^{-1}$