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Question

In a horizontal pipeline of variable cross-section, 2×102 J/kg is the change in kinetic energy per kg of the kerosene oil flowing through the pipe of length 1500 m. What will be the pressure drop between the end points of the pipe? (Take density of kerosene oil as 850 kg/m3)

A
8 N/m2
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B
10 N/m2
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C
17 N/m2
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D
1.34 N/m2
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Solution

The correct option is C 17 N/m2
Let P1 and P2 be the pressure at the inlet and outlet of the pipe respectively.
Let v1 and v2 be the velocities of oil at inlet and outlet of the pipe respectively.
Given, change in kinetic energy = 2×102 J/kg
According to the Bernoulli's theorem,
P1+12ρv21+ρgh1=P2+12ρv22+ρgh2 [h1=h2]
P1P2=12ρ(v22v21)
Change in kinetic energy per kg mass is given by
12(v22v21)=P1P2ρ
2×102=P1P2ρP1P2=ρ×(2×102)
P1P2=850×2×102
P1P2=17 N/m2
or ΔP=17 N/m2

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