Question

In a hostel, $60\%$ of the students read Hindi newspaper, $40\%$ read English newspaper and $20\%$ read both Hindi and English newspapers. A student is selected at random. Find the probability that she reads neither Hindi nor English newspapers.

• A. $\frac{1}{5}$
• B. $\frac{2}{5}$
• C. $\frac{3}{5}$
• D. $\frac{4}{5}$

Answer 1

The correct option is A $\frac{1}{5}$

Let H: the students who read Hindi newspapers, E: the students who read English newspapers.

Given P(H)=60%=0.6,P(E)=40%=0.4,P(H∩E)=20%=0.2

A student is selected at random chance that she neither reads hindi nor english=P(H' ∩E')

P(H' ∩E')=1-P(HUE)

=1-(P(H)+P(E)-P(H ∩E))

=1-(0.6+0.4-0.2)=0.2=1/5