Question

In a hot water heating system, there is a cylindrical pipe of length $28m$ and diameter $5cm$. Find the total radiating surface in the system.
[$\pi =\frac{22}{7}$]

Answer 1

Height $\left(h\right)$ of cylindrical pipe $=$ Length of cylindrical pipe $=28m$
Radius \((r)\) of circular end of pipe $=\frac{5}{2}=2.5cm$
$=\frac{2.5}{100}m=0.025m$

CSA of cylindrical pipe $=2\pi rh$
Substitute given values, we get
$=2\times \frac{22}{7}\times 0.025\times 28$
$=2\times 22\times 0.025\times 4$
$=4.4m^2$

Therefore, the area of the radiating surface of the system is $=4.4m^2$.