Question

In a house, 3 bulbs of 100 watt each lighted for 5 hours daily, 2 fans of 50 watt each used for 10 hours daily and an electric heater of 1 kW is used for half an hour daily. Calculate the total energy consumed in a month of 31 days and its cost at the rate of Rs.3.60 per kWh.

Answer 1

$$\begin{gathered} DearStudent, \\ Powerconsumedbythreebulbsof100Wfor5hoursis, \\ {P}_B=3\times 100\times 5=1500Wh=1.5kWh \\ Powerconsumedbytwofansof50Wfor10hoursis, \\ {P}_F=2\times 50\times 10=1000Wh=1kWh \\ Powerconsumedbyanelectricheaterof1kWforhalfanhouris, \\ {P}_H=1000\times 0.5=500Wh=0.5kWh \\ Totalpowerconsumedperdayis, \\ P=P_B+P_F+P_H=1.5+1+0.5=3kWh \\ Powerconsumedinamonthis, \\ {P}_m=3\times 31=\mathbf{93}\mathit{k}\mathit{W}\mathit{h} \\ Costofenergyconsumption=P_m\times 3.6=93\times 3.6=\mathit{R}\mathit{s}\mathbf{.}\mathbf{334}\mathbf{.}\mathbf{8} \\ Regards. \end{gathered}$$