In a house 3 bulbs of 25W. Each is used for 5 hours a day. Calculate units of electricity consumed in a month of 31 days. Also, find the total expenditure if 1 unit of electricity costs 2.50.
In a house 3 bulbs of 25W. Each is used for 5 hours a day. Calculate units of electricity consumed in a month of 31 days. Also, find the total expenditure if 1 unit of electricity costs 2.50.
Step 1:
Given data:
Given, No.of bulbs (n) = 3
Power of each bulb (P) = 25W = 0.025KW
Total time of usage of bulbs (t) = 5hrs per day for 31 days
= 5 x 31
= 155 hrs.
Step 2 : Definition & formula of Power:
- Power is defined as the energy consumed or released per unit time period.
- It is given as P = Energy/ time
- Its unit is the watt (W).
Step 3: Calculation
The energy consumed is given as the product of no. of bulbs, power of each bulb, and time of usage
E = nPt
= 3 x 0.025 x 155
= 11.625 KWh
We have, I unit of electricity equals 1000W or 1KW
The cost of 1 unit = 2.50
Then the cost of 11.625 kWh of energy = 11.625 x 2.50
= 29.0625
The electrical energy consumed in 31 days = 11.625KWh
The cost of total electricity = 29.0625 rupees.
Step 1:
Given data:
Given, No.of bulbs (n) = 3
Power of each bulb (P) = 25W = 0.025KW
Total time of usage of bulbs (t) = 5hrs per day for 31 days
= 5 x 31
= 155 hrs.
Step 2 : Definition & formula of Power:
- Power is defined as the energy consumed or released per unit time period.
- It is given as P = Energy/ time
- Its unit is the watt (W).
Step 3: Calculation
The energy consumed is given as the product of no. of bulbs, power of each bulb, and time of usage
E = nPt
= 3 x 0.025 x 155
= 11.625 KWh
We have, I unit of electricity equals 1000W or 1KW
The cost of 1 unit = 2.50
Then the cost of 11.625 kWh of energy = 11.625 x 2.50
= 29.0625
The electrical energy consumed in 31 days = 11.625KWh
The cost of total electricity = 29.0625 rupees.
