In a house, there are dogs, cats and parrots in the ratio3:7:5. If the number of cats was more than the number of dogs by a multiple of both 9 and 7, what is the minimum number of pets in the house?

845

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945

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1045

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none of these

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Solution

The correct option is B
945

Let $3 x, 7 x, 5 x$ be the number of dogs, cats and parrots respectively

So $4 x = 63 \times 4$

$x = 63$ total number of pets = $15 \times 63 = 945$

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In a house, there are dogs, cats and parrots in the ratio3:7:5. If the number of cats was more than the number of dogs by a multiple of both 9 and 7, what is the minimum number of pets in the house?

The correct option is B 945 Let 3x,7x,5x be the number of dogs, cats and parrots respectively So 4x=63×4 x=63 total number of pets =15×63=945

The correct option is B
945

Let $3 x, 7 x, 5 x$ be the number of dogs, cats and parrots respectively

So $4 x = 63 \times 4$

$x = 63$ total number of pets = $15 \times 63 = 945$