In a hydraulic jack as shown, mass of the car is W=800kg,A1=10cm2,A2=10m2. The minimum force F required to lift the car is: [Take g=10m/s2]
A
1N
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B
0.8N
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C
8N
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D
16N
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Solution
The correct option is B0.8N Given, A1=10cm2 A2=10m2=105cm2 F2=Wg=8000N
Pressure in the same liquid at the same level should be the same, so we can say that pressure at both the pistons are equal. F1A1=F2A2
By substituting values, F10=8000105
or F=0.8N