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Question

# In a hydraulic lift, compressed air exerts a force F1 on a small piston having a radius of 5 cm. This pressure is transmitted to a second piston of radius 15 cm. If the mass of the load to be lifted is 1350 kg, calculate the pressure acting on the smaller piston. [Take g=10 m/s2]

A
3×105 Pa
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B
2×105 Pa
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C
1.9×105 Pa
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D
1.9 Pa
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Solution

## The correct option is C 1.9×105 PaSince pressure is transmitted undiminished throughout the fluid (Pascal's law). ∴P1=P2 Thus, pressure acting on smaller piston P1=F1A1=F2A2=(1350×10)π(15×15)×10−4 ≈1.9×105 Pa

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