In a hydroelectric power station, 1000 kg of water is allowed to drop through a height of 100 m in 1 s. If the conservation of potential energy to electric energy is 60%, calculate the power output.
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Solution
In a hydroelectric power station: Mass of water (m) = 1000 kg Height (h) =1 00 m Time (t) = 1 sec Produced potential energy (PE) = mgh =1000×10×100 Joule = 10000000 joule Electrical energy =60% of potential energy =60100×1000000=600000 joule Power output = Energy × Time =600000×1watt=600000watt=6000001000 kilo - watt =600 kilo - watt