In a hydroelectric power station, 1000 kg of water is allowed to drop through a height of 100 m in 1 s. If the conservation of potential energy to electric energy is $60 %$ , calculate the power output.

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Solution

In a hydroelectric power station:
Mass of water (m) = 1000 kg
Height (h) =1 00 m
Time (t) = 1 sec
Produced potential energy (PE) = mgh $= 1000 \times 10 \times 100$ Joule = 10000000 joule
Electrical energy $= 60 %$ of potential energy $= \frac{60}{100} \times 1000000 = 600000$ joule
Power output = Energy $\times$ Time $= 600000 \times 1 w a t t = 600000 w a t t = \frac{600000}{1000}$ kilo - watt $= 600$ kilo - watt

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In a hydroelectric power station, 1000 kg of water is allowed to drop through a height of 100 m in 1 s. If the conservation of potential energy to electric energy is 60%, calculate the power output.

In a hydroelectric power station, 1000 kg of water is allowed to drop through a height of 100 m in 1 s. If the conservation of potential energy to electric energy is $60 %$ , calculate the power output.