Question

In a hydrogen atom, an electron is making 6.6 times 10 power15 rps around the nucleus in an orbit of radius0.53 Angstroms. The equivalent dipole moment is

• A. $9.06\times {10}^{-18}A{m}^2$
• B. $9.06\times {10}^{-24}A{m}^2$
• C. $3.06\times {10}^{-24}A{m}^2$
• D. $18.12\times {10}^{-24}A{m}^2$

Answer 1

The correct option is B $9.06\times {10}^{-24}A{m}^2$

Dipole moment, $\mu =\frac{evr}{2}$
$=\frac{e\left(rw\right)\left(r\right)}{2}$
$\Rightarrow \mu =\frac{e{r}^{2}w}{2}=\frac{(1.6\times {10}^{-19})(0.523\times {10}^{-10}{)}^2(6.6\times {10}^{15}\times 2\times 3.14)}{2}$
$\Rightarrow \mu =9.06\times {10}^{-24}A{m}^2$