Question

In a hydrogen atom, an electron is revolving with an angular frequency $6.28rad/s$ around the nucleus. Then the electric current is _____$\times {10}^{-19}A$

• A. $0.16$
• B. $1.6$
• C. $0.016$
• D. $16$

Answer 1

The correct option is B $1.6$

$\text{Step 1: Time period Calculation}$

Angular frequency $w=2\pi f$ $=6.28rad/sec$

$\Rightarrow T=\frac{2\pi }{w}=\frac{2\times 3.14}{6.28}=1sec$

$\text{Step 2: Calculation of current}$

We can consider a revolving electron as equivalent current.

So, lets consider Time Period of one revolution, charge crossing in one time period is e. So, current will be given by

$I=\frac{q}{t}=\frac{e}{T}$

$=\frac{1.6\times {10}^{-19}C}{1sec}=1.6\times {10}^{-19}A$

Hence, Option B is correct.