In a hydrogen atom, an electron jumps from the second orbit to the first orbit. If the frequency of the radiation emitted is 2.47 $\times$ 10 $^{x}$ cps,then value of $x$ will be ______ .

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Solution

$ν = \frac{c}{λ} = c \times R_{H} [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]$

$= 3 \times 10^{10} \times 109677.58 [\frac{1}{1^{2}} - \frac{1}{2^{2}}]$

$= 2.47 \times 10^{15}$

The value of $x$ is $15$ .

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In a hydrogen atom, an electron jumps from the second orbit to the first orbit. If the frequency of the radiation emitted is 2.47 × 10x cps,then value of x will be ______ .

ν=cλ=c×RH[1n21−1n22] =3×1010×109677.58[112−122] =2.47×1015The value of x is 15.

In a hydrogen atom, an electron jumps from the second orbit to the first orbit. If the frequency of the radiation emitted is 2.47 $\times$ 10 $^{x}$ cps,then value of $x$ will be ______ .

$ν = \frac{c}{λ} = c \times R_{H} [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]$

$= 3 \times 10^{10} \times 109677.58 [\frac{1}{1^{2}} - \frac{1}{2^{2}}]$

$= 2.47 \times 10^{15}$

The value of $x$ is $15$ .