In a hydrogen atom, the electron and proton and bound at a distance of about 0.53 A.
What are the answers to (a) and (b) above if the zero of potential energy is taken at 1.06 A separation?

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Solution

At $1.06 A^{o}$ distance, $P E = - 13.6 e V$
It is brought to zero by adding $+ 13.6 e V$
$∴ P E$ at $0.53$ is $- 13.6 e V$ and energy needed is $13.6 e V$

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In a hydrogen atom, the electron and proton and bound at a distance of about 0.53 A. What are the answers to (a) and (b) above if the zero of potential energy is taken at 1.06 A separation?

At 1.06 Ao distance, PE=−13.6eVIt is brought to zero by adding +13.6eV∴PE at 0.53 is −13.6eV and energy needed is 13.6eV

In a hydrogen atom, the electron and proton and bound at a distance of about 0.53 A.
What are the answers to (a) and (b) above if the zero of potential energy is taken at 1.06 A separation?

At $1.06 A^{o}$ distance, $P E = - 13.6 e V$
It is brought to zero by adding $+ 13.6 e V$
$∴ P E$ at $0.53$ is $- 13.6 e V$ and energy needed is $13.6 e V$