Question

In a hydrogen atom, the electron jumps from one stationary orbit for which n=1 to an orbit for which n=3. If the angular momenta of these levels are $L_i$ and $L_f$ respectively, what is the ratio $\frac{L_f}{L_i}$ ?

• A. 2:1
• B. 3:1
• C. 3:2
• D. 4:1

Answer 1

The correct option is B 3:1

According to the Bohr model, the angular momentum of an electron at an energy level n is just $\frac{nh}{2\pi }$

Therefore,
$\frac{L_f}{L_i}$ = $\frac{n_{f}h}{n_{i}h}$ = $\frac{3h}{h}$ = $3:1$