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Standard XII

Physics

The Experimental Setup

In a hydrogen...

Question

In a hydrogen like atom, electron is in 2nd excited state, the binding energy of fourth state of this atom is 13.6 eV, then

A 25 eV photon can set free the electron from the second excited state of this sample.

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3 different types of photon will be observed if electrons make transition up to ground state from the second excited state

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If 23 eV photon is used then K.E. of the ejected electron is 1 eV.

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2nd line of balmer series of this sample has same energy value as 1st excitation energy of H-atoms

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Solution

The correct options are
A A 25 eV photon can set free the electron from the second excited state of this sample.
B
3 different types of photon will be observed if electrons make transition up to ground state from the second excited state

B.E. of $4^{t h}$ state = 13.6 $\frac{z^{2}}{n^{2}} \Rightarrow 13.6 \frac{z^{2}}{n^{2}} \Rightarrow 13.6 \Rightarrow z = 4$
Sample is $B e^{3 +}$
$∴$ energy of electron in $3^{r d}$ state = – 24.17 eV
Therefore 25 eV photon will cause ionization

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