Question

In a hydrogen spectrum if electron moves from $6^{th}$ to $2^{nd}$ orbit by transition in multisteps then the number of lines in the spectrum would be:

• A. 6
• B. 8
• C. 10
• D. 9

Answer 1

The correct option is C 10

The possible transitions are $6\to 2,6\to 3,6\to 4,6\to 5,5\to 2,5\to 3,5\to 4,4\to 3,4\to 2,3\to 2$.
Or we can say for the electronic transitions from $n_2$ to $n_1$ total number of spectral lines can be given as,
$\frac{(n_2-n_1)(n_2-n_1+1)}{2}$
=$\frac{(6-2)(6-2+1)}{2}$=10
So. the number of lines in the spectrum would be 10.