MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Principle of Superposition

In a hypothet...

Question

In a hypothetical uniform and spherical planet of mass $M$ and radius $R$ , a tunnel is dug radially from its surface to its centre as shown. The minimum energy required to carry a unit mass from its centre to the surface is $k m g R$ . Find value of $k$ . Acceleration due to gravity at the surface of the planet is $g$ .

A

0.7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

0.5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

0.9

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 0.5

Suggest Corrections

thumbs-up

0

Similar questions

Q. Consider earth to be a homogeneous sphere of mass

M

R

. If we consider another spherical planet of mass

M

R

ρ

changes linearly from

ρ_{0}

5 ρ_{0}

at surface. Choose the correct statements

Q. A planet is having a mass twice to that of earth's mass and its radius as 4 times that of the earth's radius. Determine four times the acceleration due to gravity at the surface of this planet. Acceleration due to gravity at the earth's surface is

10 m s^{- 2}

Q. The value of acceleration due to gravity, at earth surface is

g

. Its value at the centre of the earth, which we assume as a.sphere of radius

R

and of uniform mass density, will be:

Q. The value of g(acceleration due to gravity) at earth's surface is

10

s^{- 2}

. Its value in m

s^{- 2}

at the centre of the earth which is assumed to be a sphere of radius R metre and uniform mass density is?

Q. Calculate energy needed for moving a mass of

4 k g

from the centre of the earth to its surface (in joule). If radius of the earth is 6400 km and acceleration due to gravity at the surface of the earth is

g = 10 m / s e c^{2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Kepler's Law

PHYSICS

Watch in App

explore_more_icon

Explore more

Principle of Superposition

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon