In a laboratory experiment to measure the specific heat capacity of copper- 0-02 kg of water at 70 -176- C was poured into a copper calorimeter with a stirrer of mass 0-16 kg initially at 15 -176-C- After stirring the final temperature reached to 45 -176-C-i- nbsp- nbsp- What is the quantity of heat released per kg of water per 1 -176-C fall in temperature-ii- nbsp- nbsp- Calculate the heat energy released by water in the experiment in cooling from 70 -176-C to 45 -176-C-iii- nbsp- Assuming that heat released by water is entirely used to raise the temperature of calorimeter 15 -176-C to 45 -176-C- calculate the specific heat capacity of copper- -Specific heat capacity of water - 4200 Jkg-1 ordm-C-1- nbsp- nbsp- nbsp- nbsp-

(i) The heat energy released by 1 kg of water, per 1 ordm;C fall in temperature , is the specific heat capacity of water, i.e. 4200 J. (ii) The total heat e ...

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Standard VIII

Physics

Heat

In a laborato...

Question

In a laboratory experiment to measure the specific heat capacity of copper, 0.02 kg of water at 70 $°$ C was poured into a copper calorimeter with a stirrer of mass 0.16 kg initially at 15 $°$ C. After stirring the final temperature reached to 45 $°$ C.
(i) What is the quantity of heat released per kg of water per 1 $°$ C fall in temperature?
(ii) Calculate the heat energy released by water in the experiment in cooling from 70 $°$ C to 45 $°$ C.
(iii) Assuming that heat released by water is entirely used to raise the temperature of calorimeter 15 $°$ C to 45 $°$ C, calculate the specific heat capacity of copper. (Specific heat capacity of water = 4200 Jkg^-1ºC^-1.

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Solution

(i) The heat energy released by 1 kg of water, per 1 ºC fall in temperature , is the specific heat capacity of water, i.e. 4200 J.

(ii) The total heat energy released by water in the experiment

= m c dt = 0.02 × 4200 × (70 – 45) = 2100 J

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A calorimeter contains 5 kg of water at 30°C. A metal of mass 4 kg at 100^oC is added to the calorimeter. The final temperature is recorded as 70^oC. Find the specific heat capacity of the metal. Given: Specific heat capacity of water 4200 J kg^–1°C^–1.

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(i) The heat energy released by 1 kg of water, per 1 ºC fall in temperature , is the specific heat capacity of water, i.e. 4200 J. (ii) The total heat energy released by water in the experiment = m c dt = 0.02 × 4200 × (70 – 45) = 2100 J

(i) The heat energy released by 1 kg of water, per 1 ºC fall in temperature , is the specific heat capacity of water, i.e. 4200 J.

(ii) The total heat energy released by water in the experiment

= m c dt = 0.02 × 4200 × (70 – 45) = 2100 J