Question

In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the number of bacteria at the end of 2 hours if the initial count was 5,06,000.

• A. 5,31,616
• B. 5,28,976
• C. 5,67,190
• D. 5,43,974

Answer 1

The correct option is A

5,31,616

Using concept of compound interest, we shall find the number of bacteria at the end of 2 hours(A).

A = P × ${[1+\frac{R}{100}]}^n$

where, P is the initial count of bacteria, R is the rate at which bacteria count increases, n is the number of hours

Given

P = 5,06,000

R = 2.5%

n = 2

A = 506000 × ${[1+\frac{2.5}{100}]}^2$

A = 5,31,616 approx.