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Question

In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the number of bacteria at the end of 2 hours if the initial count was 5,06,000.


A

5,31,616

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B

5,28,976

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C

5,67,190

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D

5,43,974

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Solution

The correct option is A

5,31,616


Using concept of compound interest, we shall find the number of bacteria at the end of 2 hours(A).

A = P × [1+R100]n

where, P is the initial count of bacteria, R is the rate at which bacteria count increases, n is the number of hours

Given

P = 5,06,000

R = 2.5%

n = 2

A = 506000 × [1+2.5100]2

A = 5,31,616 approx.


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