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Question

In a large building, there are 15 bulbs of 40W, 5 bulbs of 100W, 5 fans of 80W and 1 heater of 1kW. The voltage of the electric mains is 220V. The minimum capacity of the main fuse of the building will be.

A
12A
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B
14A
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C
8A
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D
10A
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Solution

The correct option is C 12A
ItemNo.Power
40W bulb15600 Watt
100W bulb5500 Watt
80W fan5400 Watt
1000W heater11000 Watt
Total Wattage =2500 Watt
So current capacity i=PV=2500220=12511=11.3612 Amp.

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