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Question

In a lead storage battery, the anode reaction is, Pb+H2SO4PbSO4+2H++2e
Weight in g of Pb would be used up for battery to use for 1 ampere hour is___________. (write the nearest integer value)

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Solution

The current passed is 100 ampere hour.
The number of Faradays passed is I(A)×t(s)96500=1×360096500=3.73×102.
1 mole of Pb will be deposited by 2 Faradays of electricity.
The molar mass of Pb is 207 g/mol.
The mass of lead deposited is 3.73×102×2072=3.86g4.

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