Question

In a lifting machine, an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10,000 N by a distance of 0.8 m. Determine the effort lost in friction

• A. 100 N
• B. 120 N
• C. 80 N
• D. 0 N

Answer 1

The correct option is A 100 N

$\text{effort}{F}_1=500N$

$\text{distance}{x}_1=20m$

$\text{load}{F}_2=10,000N$

$\text{distance}{x}_2=0.8m$

$\text{let, Energy lost in friction}=W$

$F_1{x}_1=F_2{x}_2+w$

$\text{5}00\times 20=10.000\times \frac{8}{10}+w$

$\text{w}=2000\text{Joule}$

$\therefore 2000=F\times x_1$

$\text{2}000=F\times 20\text{,}F=\text{effort lost in friction}$

$\text{on}f=100N$

Ans.- option-A