A machine has a velocity ratio of 4. It is used to raise a load of 200 N by 4 m using an effort of 20 kgf. Find the work done on the machine. Take $g = 10 m s^{- 2}$ .

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In a lifting machine, an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10000 N by a distance of 0.8 m. Determine the velocity ratio and mechanical advantage?

The correct option is D 25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=EdLdVR=200.8VR=25the load is 10,000N and effort=500NMA=loaddeffortdMA=10000500MA=20

In a lifting machine, an effort of $500$ N is to be moved by a distance of $20$ m to raise a load of $10000$ N by a distance of $0.8$ m. Determine the velocity ratio and mechanical advantage?

The correct option is D 25 and 20
Distance moved by effort is 20m,that of load is 0.8m

$V R = \frac{E_{d}}{L_{d}}$

$V R = \frac{20}{0.8}$

$V R = 25$

the load is 10,000N and effort=500N

$M A = \frac{l o a d_{d}}{e f f o r t_{d}}$

$M A = \frac{10000}{500}$

$M A = 20$