In a lithium ion Li2+, an orbit has a diameter of about 3.18∘A. What is the maximum number of electrons that can be accommodated in this orbit?
Open in App
Solution
Diameter =3.18∘A
Radius of the orbit =3.182=1.59∘A ⇒1.59=0.53×n2Z Where n = the orbit and Z = 3 as a lithium ion is given →n2=4.770.53=9 ⇒n=3 Therefore, the maximum number of atoms that can be accommodated in this orbit will be 2n2=18