In a long cylindrical wire of radius R, magnetic induction varies with the distance r from axis as B=Crα, where C&α are constant. Find the function of current density in wire with the distance from the axis of wire.
A
[(α+1)Cμ0]rα+1
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B
[(α−1)μ0]rα+1
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C
[(α+1)Cμ0]rα−1
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D
[(α−1)μ0]r1−α
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Solution
The correct option is C[(α+1)Cμ0]rα−1
At a distance r from the axis of wire, we consider a closed path M as shown in the figure.
Applying Ampere's circuital law on this path
∮→B⋅→dl=μ0Ienclosed..........(1)
If J(x) is the current density inside the wire as a function of distance x from the axis of wire, the enclosed current within the closed path M is given by integrating the current in the elemental ring of radius x and width dx considered in the cross-section of wire as shown in the figure.
Ienclosed=∫r0J(x)⋅2πxdx........(2)
From (1) and (2) we have
∮Bdl=μ0∫r0J(x)⋅2πxdx
B×2πr=μ0∫r0J(x)⋅2πxdx
Crα+1=μ0∫r0J(x)xdx(∵B=Crα)
Differentiating the above expression with respect to x gives