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Question

In a long cylindrical wire of radius R, magnetic induction varies with the distance r from axis as B=Crα, where C & α are constant. Find the function of current density in wire with the distance from the axis of wire.

A
[(α+1)Cμ0]rα+1
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B
[(α1)μ0]rα+1
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C
[(α+1)Cμ0]rα1
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D
[(α1)μ0]r1α
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Solution

The correct option is C [(α+1)Cμ0]rα1

At a distance r from the axis of wire, we consider a closed path M as shown in the figure.

Applying Ampere's circuital law on this path

Bdl=μ0Ienclosed ..........(1)

If J(x) is the current density inside the wire as a function of distance x from the axis of wire, the enclosed current within the closed path M is given by integrating the current in the elemental ring of radius x and width dx considered in the cross-section of wire as shown in the figure.

Ienclosed=r0J(x)2πxdx ........(2)

From (1) and (2) we have

Bdl=μ0r0J(x)2πxdx

B×2πr=μ0r0J(x)2πxdx

Crα+1=μ0r0J(x)xdx (B=Crα)

Differentiating the above expression with respect to x gives

(α+1)Crα=μ0J(r)r

J(r)=[(α+1)C)μ0]rα1

Hence, option (C) is correct.

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