In a lottery, there are 6 prizes and 24 blanks. What is the probability of not getting a prize?
(a) $\frac{3}{4}$ (b) $\frac{3}{5}$ (b) $\frac{4}{5}$ (d) $\frac{2}{9}$

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Solution

Number of prizes = 6
Number of blanks = 24
Total number of tickets = 6 + 24= 30
P(not getting a prize ) $= \frac{24}{30} = \frac{4}{5}$

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In a lottery, there are 6 prizes and 24 blanks. What is the probability of not getting a prize? (a) 34 (b) 35 (b) 45 (d) 29

Number of prizes = 6 Number of blanks = 24 Total number of tickets = 6 + 24= 30 P(not getting a prize ) =2430=45

In a lottery, there are 6 prizes and 24 blanks. What is the probability of not getting a prize?
(a) $\frac{3}{4}$ (b) $\frac{3}{5}$ (b) $\frac{4}{5}$ (d) $\frac{2}{9}$

Number of prizes = 6
Number of blanks = 24
Total number of tickets = 6 + 24= 30
P(not getting a prize ) $= \frac{24}{30} = \frac{4}{5}$