In a machine, a load of 490 N is supported by an effort of 7N. If the distance of fulcrum from the point where the load acts is 10m, find the mechanical Advantage and length of the effort arm.

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Solution

Load = 490 N

Effort = 70 N

Load arm = 10m

Effort arm = ?

$l o a d \times l o a d a r m = e f f o r t \times e f f o r t a r m$

$490 N \times 10 = 70 N \times x$

$x = \frac{4900}{70}$

x = 70m

Effort arm = 70m

Mechanical Advantage = $\frac{l o a d}{e f f o r t}$

= $\frac{490}{70}$ = 7

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In a machine, a load of 490 N is supported by an effort of 7N. If the distance of fulcrum from the point where the load acts is 10m, find the mechanical Advantage and length of the effort arm.

Load = 490 N Effort = 70 N Load arm = 10m Effort arm = ? load×load arm =effort×effort arm 490N×10=70N×x x=490070 x = 70m Effort arm = 70m Mechanical Advantage = loadeffort = 49070 = 7

Load = 490 N

Effort = 70 N

Load arm = 10m

Effort arm = ?

$l o a d \times l o a d a r m = e f f o r t \times e f f o r t a r m$

$490 N \times 10 = 70 N \times x$

$x = \frac{4900}{70}$

x = 70m

Effort arm = 70m

Mechanical Advantage = $\frac{l o a d}{e f f o r t}$

= $\frac{490}{70}$ = 7