Question

In a machine an effort of 10 𝑘𝑔𝑓 is applied to lift a load of 100 𝑘𝑔𝑓. What is its mechanical advantage?

Answer 1

Solution:
Given,
$Effort\left(E\right)=10kgf$
$Load\left(L\right)=100kgf$
Mechanical advantage $(M.A.)=?$
It is the ratio of load to effort.
$M.A.=\frac{Load}{effort}$
$=\frac{(}{1}00kgf\left)/\right(10kgf)$
$=10$
Hence, mechanical advantage is 10.