In a machine, an effort of $10 k g f$ is applied to lift a load of $100 K g f$ . What is the mechanical advantage of the machine?

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Solution

Step 1: Given data
Effort = $10 k g f$
Load = $100 K g f$
Step 2: Formula used
$M e c h a n i c a l a d v a n t a g e = \frac{L o a d}{E f f o r t}$
Step 3: Calculation
$M . A = \frac{L o a d}{E f f o r t} = \frac{100 k g f}{10 k g f} = \frac{100}{10} = 10$
Hence, the mechanical advantage of the machine is 10.

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