In a magic square each row, column and diagonal have the same sum, then the values of A and B respectively are ___________.
$1$ $- 10$ $0$
A $- 3$ $- 2$
$- 6$ $4$ B

- 7, - 4

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- 4, - 7

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- 4, - 6

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- 6, - 4

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Solution

The correct option is B $- 4, - 7$
Addition of the numbers in $1$ st row = $1 - 10 + 0 = - 9$

Therefore each row, column and diagonal will have the same sum = $- 9$

$∴$ $1 + A - 6 = - 9$

$∴$ $A = - 4$

Similarly,

$- 6 + 4 + B = - 9$

$∴$ $B = - 7$

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Similar questions

In a magic square each row, column and diagonal have the same sum. Check which of the following is a magic square.

5	− 1	− 4	1	− 10	0
− 5	− 2	7	− 4	− 3	− 2
0	3	− 3	− 6	4	− 7
(i)			(ii)

Q. Question 7
In a magic square each row, column and diagonal have the same sum. Check which of the following is a magic square.

\begin{matrix} 5 & - 1 & - 4 & 1 & - 10 & 0 - 5 & - 2 & 7 & - 4 & - 3 & - 2 0 & 3 & - 3 & - 6 & 4 & - 7 (i) & (i i) \end{matrix}

13	$4 \frac{1}{4}$
$6 \frac{3}{4}$	A	B
8		$5 \frac{1}{2}$

Complete the given magic square such that all the rows, columns and diagonals - add to the same number. What is A

+

B here?

Question 3
In a “magic square”. The sum of the numbers in each row, in each column and along the diagonals is the same. Is this a magic square?
$\begin{matrix} \frac{4}{11} & \frac{9}{11} & \frac{2}{11} \frac{3}{11} & \frac{5}{11} & \frac{7}{11} \frac{8}{11} & \frac{1}{11} & \frac{6}{11} \end{matrix}$
$(Along the first row \frac{4}{11} + \frac{9}{11} + \frac{2}{11} = \frac{15}{11})$

If
A = {1, 2, 3, 4}

B = {3, 4, 5, 6, 7}

C = {6, 7, 8, 9}

D = {7, 8, 9, 10}

$\begin{matrix} C o l u m n A & C o l u m n B 1. A \cup B & a . {3, 4, 6, 7} 2. A \cap B & b . \emptyset 3. (B \cap C) \cup D & c . {3, 4} 4. B \cup C \cup D & d . {3, 4, 5, 6, 7, 8, 9, 10} 5. (A \cap B) \cap (B \cup C) & e . {1, 2, 3, 4, 5, 6, 7} f . {6, 7, 8, 9, 10} g . {7} \end{matrix}$

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In a magic square each row, column and diagonal have the same sum, then the values of A and B respectively are ___________.1−100A−3−2−64B

The correct option is B −4,−7Addition of the numbers in 1 st row = 1−10+0=−9Therefore each row, column and diagonal will have the same sum =−9∴ 1+A−6=−9∴ A=−4Similarly,−6+4+B=−9∴ B=−7

In a magic square each row, column and diagonal have the same sum, then the values of A and B respectively are ___________.
$1$ $- 10$ $0$
A $- 3$ $- 2$
$- 6$ $4$ B

The correct option is B $- 4, - 7$
Addition of the numbers in $1$ st row = $1 - 10 + 0 = - 9$

Therefore each row, column and diagonal will have the same sum = $- 9$

$∴$ $1 + A - 6 = - 9$

$∴$ $A = - 4$

Similarly,

$- 6 + 4 + B = - 9$

$∴$ $B = - 7$