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Question

In a mass spectrograph mass number and charge of ion A are 24 and +2e respectively. Mass number and charge of ion B are 22 and +e. If both ions has same speed and the radius of path traced by ion A is 24 cm then radius of path traced by ion B will be

A
55 cm
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B
11 cm
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C
44 cm
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D
24 cm
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Solution

The correct option is C 44 cm
A: r=mvqB
24=24×v2×B(1)

B: r=22×v1×B(2)
Dividing 2 by 1
r24=22vB2B24v
r=44cm

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