In a material the rnagnetic field intensity is $H = 1400 A / m$ when magnitude flux density $B = 2 W b / m^{2}$ . When H is reduces to 700 A/m at $B = 1.4 W b / m^{2}$ ,the change in permeability is
454.73

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Solution

The correct option is A 454.73
For case 1:

$B = μ H$

$μ = \frac{B}{H} = \frac{2}{1400} = \frac{1}{700}$

$μ_{r 1} = \frac{1}{700 μ_{0}} = 1136.82$ …. (i)

For case 2:

$μ_{r 2} = \frac{1.4}{700 μ_{0}} = \frac{1}{500 μ_{0}} = 1591.55$ …. (ii)

The change on permeability ,

$Δ μ_{r} = μ_{r 2} - μ_{r 1}$

$= 1591.55 - 1136.82$

$= 454.73$

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In a material the rnagnetic field intensity is H=1400A/m when magnitude flux density B=2 Wb/m2. When H is reduces to 700 A/m at B=1.4 Wb/m2 ,the change in permeability is454.73

The correct option is A 454.73For case 1: B=μH μ=BH=21400=1700 μr1=1700μ0=1136.82 …. (i) For case 2: μr2=1.4700μ0=1500μ0=1591.55…. (ii) The change on permeability , Δμr=μr2−μr1 =1591.55−1136.82 =454.73

In a material the rnagnetic field intensity is $H = 1400 A / m$ when magnitude flux density $B = 2 W b / m^{2}$ . When H is reduces to 700 A/m at $B = 1.4 W b / m^{2}$ ,the change in permeability is
454.73