In a Math test two students while solving a quadratic equation committed the following mistakes:
(i) One of them made a mistake in the constant term and got the roots as 5 and 9.
(ii) Another one committed an error in the coefficient of x and got the roots as 12 and 4.
But, in the meantime, they realised that they are wrong and they managed to get it right jointly. Find the correct quadratic equation.

$x^{2} - 44 x + 14 = 0$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$2 x^{2} + 7 x - 24 = 0$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$x^{2} - 14 x + 48 = 0$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$3 x^{2} - 17 x + 52 = 0$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$x^{2} - 14 x + 48 = 0$

Since the first person made a mistake in constant term.
Therefore, the sum of roots = 14
and the second person made a mistake in coefficient of x
Therefore, product of roots = 48
Required quadratic equation is $x^{2} - 14 x + 48 = 0$

Suggest Corrections

Similar questions

Q. In the Maths test two students, while solving a quadratic equation, committed the following mistakes:
(i) One of them made a mistake in the constant term and got the roots as 5 and 9.
(ii) Another one committed an error in the coefficient of x and got the roots as 12 and 4.
But, in the meantime, they realised that they are wrong and they managed to get it right jointly. Find the correct quadratic equation.

Two students, while solving a quadratic equation, committed the following mistakes:
(i) One of them made a mistake in the constant term and got the roots as $5$ and $9$ .
(ii) Another one committed an error in the coefficient of $x$ and got the roots as $12$ and $4$ .
But, in the meantime, they realised that they are wrong and they managed to get it right jointly.

Find the correct quadratic equation.

Q. In the Maths test two representatives, while solving a quadratic equation, committed the following mistakes:
(i) One of them made a mistake in the constant term and got the roots as

5

and

9

.
(ii) Another one committed an error in the coefficient of x and got the roots as

12

and

4

.
But in the meantime, they realised that they are wrong and they managed to get right jointly. Find the correct quadratic equation.

In the Maths test two students, committed the following mistakes while solving a quadratic equation :
(i) One of them made a mistake in the constant term and got the roots as 2 and 4.
(ii) Another one committed an error in the coefficient of x and got the roots as 3 and 5.
But, they realised that they are wrong and they managed to get it right jointly. Find the correct quadratic equation.

Ganesh and Lokesh solved a quadratic equation. In solving it, Ganesh made a mistake in the constant term and got the roots as 6 and 7, while Lokesh made a mistake in the coefficient of x only and obtained the roots as 4 and 10. The correct roots of the equation are:

Join BYJU'S Learning Program

The correct option is C x2−14x+48=0 Since the first person made a mistake in constant term. Therefore, the sum of roots = 14 and the second person made a mistake in coefficient of x Therefore, product of roots = 48 Required quadratic equation is x2−14x+48=0

The correct option is C
$x^{2} - 14 x + 48 = 0$

Since the first person made a mistake in constant term.
Therefore, the sum of roots = 14
and the second person made a mistake in coefficient of x
Therefore, product of roots = 48
Required quadratic equation is $x^{2} - 14 x + 48 = 0$