Question

In a medium of dielectric constant $K$, the electric field is $\overrightarrow{E}$. If ${ϵ}_0$ is permittivity of the free space, the electric displacement vector is :

• A. $\frac{K\overrightarrow{E}}{{ϵ}_0}$
• B. $\frac{\overrightarrow{E}}{{Kϵ}_0}$
• C. $\frac{{ϵ}_0\overrightarrow{E}}{K}$
• D. ${Kϵ}_0\overrightarrow{E}$

Answer 1

Answer: (D)

${Kϵ}_0\overrightarrow{E}$

Electric displacement vector $D$ is given by,
As $\epsilon ={\epsilon }_{0}K$
$\therefore \overrightarrow{D}={\epsilon }_{0}K\overrightarrow{E}$