In a Mendel's monohybrid cross, the percentage of true breeding dominant and pure recessive in F1 generation would be
A
50%
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B
25%
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C
75%
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D
0%
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Solution
The correct option is D 0% In a Mendel's experiment, a cross between two pure (homozygous) patterns in which the inheritance pattern of only one of the contrasting characters is studied is called monohybrid cross. With true-breeding parents (one homozygous dominant, one homozygous recessive), all of the F1 progeny will be heterozygous and show the dominant phenotype, e.g,. Tt. Hence, 0% progeny show true-breeding dominant and pure recessive in F1 generation.