Question

In a metallic triangular sheet ABC. AB = BC = 1. If m is mass of sheet, what is the moment of inertia about AC

• A. $\frac{m{l}^2}{4}$
  
• B. $\frac{m{l}^2}{12}$
  
• C. $\frac{m{l}^2}{6}$
  
• D. $\frac{m{l}^2}{18}$

Answer 1

The correct option is B $\frac{m{l}^2}{12}$



Moment of inertia of triangular sheet ABC about $AC=\frac{1}{2}$ moment of inertia of
square ABCD about $AC=\frac{1}{2}\left(2M\right)\frac{l^2}{12}=\frac{M{l}^2}{12}$