Question

In a meter bridge experiment, the resistance in the left gap is equal to $2\Omega$ and the bridge wire is divided in the ratio $1:2$ by the jockey at the null point. The value of the resistance of the resistor in the right gap of the meter bridge is

​​​​​​​$[$0.77 Mark$]$

• A. $4\Omega$
• B. $2\Omega$
• C. $6\Omega$
• D. $3\Omega$

Answer 1

The correct option is A $4\Omega$

Meter bridge is based on the principle of Wheatstone bridge.


At null deflection in the galvanometer,

$\frac{P}{Q}=\frac{l_1}{l_2}$

$\Rightarrow \frac{2}{Q}=\frac{1}{2}\Rightarrow Q=4\Omega$